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  • zogwarg@awful.systems
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    7 days ago

    Day 11

    Some hacking required to make JQ work on part 2 for this one.

    Part 1, bruteforce blessedly short
    #!/usr/bin/env jq -n -f
    
    last(limit(1+25;
      [inputs] | recurse(map(
        if . == 0 then 1 elif (tostring | length%2 == 1) then .*2024 else
          tostring | .[:length/2], .[length/2:] | tonumber
        end
      ))
    )|length)
    
    Part 2, some assembly required, batteries not included
    #!/usr/bin/env jq -n -f
    
    reduce (inputs|[.,0]) as [$n,$d] ({};     debug({$n,$d,result}) |
      def next($n;$d): # Get next           # n: number, d: depth  #
          if $d == 75                    then          1
        elif $n == 0                     then [1          ,($d+1)]
        elif ($n|tostring|length%2) == 1 then [($n * 2024),($d+1)]
        else #    Two new numbers when number of digits is even    #
          $n|tostring| .[0:length/2], .[length/2:] | [tonumber,$d+1]
        end;
    
      #         Push onto call stack           #
      .call = [[$n,$d,[next($n;$d)]], "break"] |
    
      last(label $out | foreach range(1e9) as $_ (.;
        # until/while will blow up recursion #
        # Using last-foreach-break pattern   #
        if .call[0] == "break" then break $out
        elif
          all( #     If all next calls are memoized        #
              .call[0][2][] as $next
            | .memo["\($next)"] or ($next|type=="number"); .
          )
        then
          .memo["\(.call[0][0:2])"] = ([ #                 #
              .call[0][2][] as $next     # Memoize result  #
            | .memo["\($next)"] // $next #                 #
          ] | add ) |  .call = .call[1:] # Pop call stack  #
        else
          #    Push non-memoized results onto call stack   #
          reduce .call[0][2][] as [$n,$d] (.;
            .call = [[$n,$d, [next($n;$d)]]] + .call
          )
        end
      ))
      # Output final sum from items at depth 0
      | .result = .result + .memo["\([$n,0])"]
    ) | .result